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| | #1 |
| Lives for gear | hardware insert to balanced patch bay question
hey guys, bit of a noodle scratcher. so i'm soldering my inserts. they look like this: ![]() and they're going to connect to 2 balanced bantam patch sockets, one for send, one for return (basically a Y cable). the patch bay has 3 pins on the back of each socket to solder to as shown in my diagram- lets say this is my send socket ![]() should i connect the socket: a) without the ground A connected b) without the ring B connected c) with all 3 connected but at the insert jack end, the A and B would both be connected to ground please note that my insert jack has the tip as return also note that the patch bay will be connected to balanced outboard. I've generally used method c) in the past. what say you slutz? |
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| | #2 |
| Moderator |
ok.... you need 2 sockets both rows (upper and lower) for one channel of AUX wire the + signal to the tip of the balanced socket and the earth to the earth do not connect the - signal of the patchbay if you use non transformer balanced gear *that cannot see an unbalanced input (at it's own output) balance the send and returns before going into the patchbay half normalise the connections on the patchbay (insert cable into top socket breaks the connection, insert cable into lower socket doesn't break the connection) top row socket one send from mixer bottom row socket one input of FX machine top row socket two output of FX machine bottom row of socket two return to mixer cheers |
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| | #3 |
| Lives for gear |
cheers! we're on the same wave-length! i was thinking the answer has to be (b) EDIT: re normalising. yea i am of course going to semi-normalise, didn't want to add that info as it could complicate the problem. |
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