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Originally Posted by Kiwiburger Let's assume we are talking about a 16 bit CD. If you have very quiet audio information - say around 48dB, then that is only going to use around 8 bits of the total 16 bits. For the pedants - all 16 bits will be 'used', but only 8 of them would be significant. So the signal will have all the graininess of an 8 bit sample - while still in the relatively noiseless digital domain. |
Get back to us when you include the magic linearizing powers of dither. The only difference is the noise-floor.
8 bits or 80.
Forget the grain.
DC