Quote:
Originally Posted by dale116dot7  Can I just fade in one tap as the other one fades out? |
Yes, I think this is a way to look at it. In that each tap is really two taps next to each other. The value that should be summed to the output will be a linear combination of the two neighboring taps ie.
27/32*mem[n] + 5/32*mem[n+1], then 26/32*mem[n] + 6/32*mem[n+1], then 25/32*mem[n] + 7/32*mem[n+1]...
then a memory address change occurs when the sequence reaches this point:
1/32*mem[n] + 31/32*mem[n+1], then 0/32*mem[n] + 32/32*mem[n+1], then 31/32*mem[n+1] + 1/32*mem[n+2]...
if you use 32 steps between each sample.
It's of course OK if a tap doesn't move during a given sample time, if it takes multiple sample times to set up the new move.
The lead sample will be either n+1 or n-1 depending on which direction the tap is moving.
-Casey